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5x+5x^2=550
We move all terms to the left:
5x+5x^2-(550)=0
a = 5; b = 5; c = -550;
Δ = b2-4ac
Δ = 52-4·5·(-550)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-105}{2*5}=\frac{-110}{10} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+105}{2*5}=\frac{100}{10} =10 $
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